I am trying to retrieve a file name from the server of the file that has just been uploaded. The problem is that I am getting an undefine index on my php variable below:
Undefined index: fileimagename in /web/stud/xxx/Mobile_app/QandATable.php on line 19
What I am trying to do is that user uploads the form which is done by the php script (imageupload.php), Now when uploading stops it uses the javascript function which is on a seperate page (QandATable.php, same page as the ) to display the message if upload is successful and this would append the name of the file uploaded.
So my question is how can I fix the undefined variable and how can I get the javascript function in the QandATable.php to retireve the file name from imageupload.php?
Below is code which consists the undefined variable and javascript function (QandATable.php):
<?php
session_start();
$fileimagename = $_SESSION['fileimagename'];
?>
<script type="text/javascript">
function stopImageUpload(success){
var fileimagename = <?php echo $fileimagename; ?>;
var result = '';
if (success == 1){
result = '<span class="msg">The file was uploaded successfully!</span><br/><br/>';
$('.listImage').append(fileimagename + '<br/>');
}
else {
result = '<span class="emsg">There was an error during file upload!</span><br/><br/>';
}
return true
};
</script>
Below is php script which uploads the file into the server: (imageupload.php)
<?php
session_start();
if (isset($_POST['fileimagename'])) {
$_SESSION['fileimagename'] = $_SESSION[' $_FILES['fileImage']['name']'];
}
if( file_exists("ImageFiles/".$_FILES['fileImage']['name'])) {
$parts = explode(".",$_FILES['fileImage']['name']);
$ext = array_pop($parts);
$base = implode(".",$parts);
$n = 2;
while( file_exists("ImageFiles/".$base."_".$n.".".$ext)) $n++;
$_FILES['fileImage']['name'] = $base."_".$n.".".$ext;
move_uploaded_file($_FILES["fileImage"]["tmp_name"],
"ImageFiles/" . $_FILES["fileImage"]["name"]);
$result = 1;
}
else
{
move_uploaded_file($_FILES["fileImage"]["tmp_name"],
"ImageFiles/" . $_FILES["fileImage"]["name"]);
$result = 1;
}
?>
<script language="javascript" type="text/javascript">
window.top.window.stopImageUpload(<?php echo $result;?>,'<?php echo $fileimagename;?>');
</script>
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